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-30=x^2+11x
We move all terms to the left:
-30-(x^2+11x)=0
We get rid of parentheses
-x^2-11x-30=0
We add all the numbers together, and all the variables
-1x^2-11x-30=0
a = -1; b = -11; c = -30;
Δ = b2-4ac
Δ = -112-4·(-1)·(-30)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*-1}=\frac{10}{-2} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*-1}=\frac{12}{-2} =-6 $
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